5+x^2+(6-x)(6+x)=8x-39

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Solution for 5+x^2+(6-x)(6+x)=8x-39 equation: 



5+x^2+(6-x)(6+x)=8x-39

We move all terms to the left:

5+x^2+(6-x)(6+x)-(8x-39)=0

We add all the numbers together, and all the variables

x^2+(-1x+6)(x+6)-(8x-39)+5=0

We get rid of parentheses

x^2+(-1x+6)(x+6)-8x+39+5=0

We multiply parentheses ..

x^2+(-1x^2-6x+6x+36)-8x+39+5=0

We add all the numbers together, and all the variables

x^2+(-1x^2-6x+6x+36)-8x+44=0

We get rid of parentheses

x^2-1x^2-6x+6x-8x+36+44=0

We add all the numbers together, and all the variables

-8x+80=0

We move all terms containing x to the left, all other terms to the right

-8x=-80

x=-80/-8

x=+10

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